fixed the gold_oa definition

beta
Antonis Lempesis 3 years ago
parent 43852bac0e
commit 461bf90ca6

@ -17,6 +17,6 @@ left outer join ${stats_db_name}.indi_pub_green_oa green on green.id=r.id;
-- GOLD OA:
create table ${stats_db_name}.result_gold as
select r.id, case when green.green_oa=1 then true else false end as green
select r.id, case when gold.gold_oa=1 then true else false end as gold
from ${stats_db_name}.result r
left outer join ${stats_db_name}.indi_pub_gold_oa green on green.id=r.id;
left outer join ${stats_db_name}.indi_pub_gold_oa gold on gold.id=r.id;
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